Write pseudo-code flowchart to input the year and to test and display whether the given year is leap year or not?

Today, let's unravel the mystery of leap years together. Buckle up as we delve into creating a pseudo-code and a Python script that will make identifying leap years a breeze.

Firstly, let's understand the logic behind leap years. A leap year is divisible by 4, but if it's divisible by 100, it also needs to be divisible by 400 to be considered a leap year. Now, let's translate this into a simple pseudo-code:

plaintext

Start
  Read year from the user
  If (year is divisible by 4 and not divisible by 100) or (year is divisible by 400)
    Display "Leap year"
  Else
    Display "Not a leap year"
End

Voila! That's our pseudo-code. Now, let's convert this into Python, making it even more engaging:

python

# Let's get the year from the user
year = int(input("Enter the year: "))

# Check for leap year conditions
if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):
    print(f"{year} is a Leap Year!")
else:
    print(f"{year} is Not a Leap Year.")

How cool is that? We've translated the logical steps into a language that our computer can understand.

Feel free to use this code snippet in your projects or assignments. Exploring coding is like solving a puzzle – piece by piece, you uncover the bigger picture. If you ever feel stuck, remember, there's a vibrant community eager to help you grow.

And there you have it, your journey into leap years made simple and enjoyable. Happy coding!